This IC 555 Li-ion battery charger circuit was build to charge a couple of series Lithium cells (3.6 volts each, 1 Amp Hour capacity).
The charger operates by supplying a short current pulse through a series resistor and then monitoring the battery voltage to determine if another pulse is required. The current can be adjusted by changing the series resistor or adjusting the input voltage. When the battery is low, the current pulses are spaced close together so that a somewhat constant current is present. As the batteries reach full charge, the pulses are spaced farther apart and the full charge condition is indicated by the LED blinking at a slower rate.
A zener voltage reference (2.5 volts) is used on pin 2 of the comparator so that the comparator output will switch low, triggering the 555 timer when the voltage at pin 7 is less than 2.5 volts. The 555 output turns on the 2 transistors and the batteries charge for about 30 milliseconds. When the charge pulse ends, the battery voltage is measured and divided down by the combination 22K, 8.2K and 620 ohm resistors so when the battery voltage reaches 8.2 volts, the input at pin 7 of the comparator will rise slightly above 2.5 volts and the circuit will stop charging.
The proposed IC 555 Li-ion battery charger circuit could be used to charge other types of batteries such as Ni-Cad, NiMh or lead acid, but the shut-off voltage will need to be adjusted by changing the 8.2K and 620 ohm resistors so that the input to the comparator remains at 2.5 volts when the terminal battery voltage is reached.
For example, to charge a 6 volt lead acid battery to a limit of 7 volts, the current through the 20K resistor will be (7-2.5)/ 20K = 225 microamps. This means the combination of the other 2 resistors (8.2K and 620) must be R=E/I = 2.5/ 225 uA = 11,111 ohms. But this is not a standard value, so you could use a 10K in series with a 1.1K, or some other values that total 11.11K
Be careful not to overcharge the batteries. I would recommend using a large capacitor in place of the battery to test the circuit and verify it shuts off at the correct voltage.
r k says
which pin of IC-555 is grounded?
admin says
pin#1
Marjan Markovski says
tnx. I have tested it but the diode does not turn off even when battery is full. I have even put two full batteries in a serie and the same again
admin says
replace the 22k resistor with a preset and adjust it until the LED just turns ON at full charge….
Marjan says
dear I finally made the circuit but when put the battery after a few seconds the transistor 2907 started smoke a little and was very hot. should I put some cooling or change with some other
admin says
yes you can add a heatsink or replace the 2N2907 with BD140, I am glad you could make it successfully
Marjan says
Dear, what number is the pin of ic555 that is connected with the pin 4 of ic741?
admin says
it’s pin#1, and also connect pin#4 of ic555 with its pin#8
Marjan Markovski says
can you help me because I don’t know how, Im not too good in electronics. Thanks
admin says
please use Ohms law to calculate the value of the required resistor in place of 18 ohm
Marjan Markovski says
*higher capacity
Marjan Markovski says
Sorry but allso need to ask you If I should change something else too because my battery is bighed capacity (samsung 3.8v 2600mAh) Thanks
admin says
you may have to calculate and replace the 18 ohm resistor appropriately
Marjan says
just one more question please, what value should be the two resistors to make charger for one mobile battery?
admin says
please calculate it as per the indicated example and formula….
Marjan says
what is the value of the other capacitor?
admin says
0.047uF