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IC 7812, 7805 Current Booster Circuit

Last Updated on July 19, 2019 by Admin 8 Comments

Current in all 78XX ICs such as 7812, 7805, 7824 etc is internally restricted to 1 amp only. In this post we learn how to boost current from these ICs using an outboard transistor circuit with a 78XX circuit.

There are several options of pulling extra current from a 78XX type voltage regulator lC than it was original rating, however the majority of techniques have their down sides, In case, for example, a power transistor is attached in parallel with the IC, the supply voltage may not be safeguarded from short-circuits.

That may, naturally, be dealt with with the addition of a current sensor in the form of an additional transistor that, while in overload situations, cuts off the base current for the power transistor. Nevertheless this particular remedy can experience great power loss in the course of short-circuit situations, that is not truly suitable either.

increase boost current in 7812, 7805 and all 78XX circuit using transistor

The current booster circuit for 7812, 7805 ICs offered in this article demonstrates that a less complicated solution might be achievable: the power transistor, T1, is presented with an emitter resistor!

This successfully handles the problem, due to the fact the current via T1 is then proportionate to the current delivered through the voltage regulator. In case the 78XX regulator and T1 are attached onto the same heatsink, the transistor is additionally thermally guarded!

The output voltage will depend merely on the type of voltage regulator used and, as presented here, the circuit is well suited for currents as much as 2 A. If greater values are needed, a number of parts might have to be modified based on the given chart below.

To increase currents over 7 A, transistor T1 should be substituted by a couple of parallel attached transistors each of containing an emitter resistor, R1 and R1' respectively.

78XX voltage regulator current voltage boost chart table

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About Admin

Hey friends, Thanks a bunch for stopping by this site! I am an engineer with a Bachelor of Engineering in Electronics and Telecommunication. One of my passions is gathering information from all sorts of electronics books and tutorials. I then take that information and compile it into a language that is super easy to understand. My goal is to make those complex electronics circuit concepts and technical terms much more accessible for all the new and budding electronics engineers out there. I can also design customized circuit diagrams as required by the users.
If you have any questions related to this field, please do not hesitate to drop a comment! I am always here and ready to help you out with any queries you might have. I cannot wait to hear from you!

Reader Interactions

Comments

  1. Sudy says

    October 20, 2023 at 9:14 am

    Thank you for your idea!

    Reply
    • admin says

      November 2, 2023 at 9:37 am

      You are welcome Sudy!!

      Reply
  2. mov ax,bx says

    October 5, 2022 at 11:19 pm

    The circuit is using outdated transistors and is quite more expensive than using a suitable voltage regulator that handles the current directly. Most modern regulators are a lot more effective than this one, have additional features like low dropout voltage, better ripple rejection, smaller capacitors requirements, and _real_ thermal protection. In this circuit, by putting both elements on the same heatsink, at the time the transistor heat has traveled all the way through the heatsink and triggers 78xx thermal protection, the transistor is long gone. Don’t use this. There are cheap alternatives: Question above, use a LM317 plus 3 resistors, voila: Battery charger (see LM317 datasheet). 2 resistors, 2 capacitors, 1 diode, 1 inductor, voila: 5 A current with XL5006.

    Reply
    • admin says

      October 13, 2022 at 1:49 pm

      You can use TIP32 or TIP36.
      This design is highly customizable.

      Reply
  3. Denis says

    October 13, 2020 at 7:00 pm

    I would like to protect the battery from overcharging

    Reply
    • admin says

      October 13, 2020 at 7:39 pm

      12V will not charge a 12V battery….

      for auto cut off you can add the following op amp stage at the output of the above 78XX design

      https://makingcircuits.com/blog/automatic-12v-battery-charger-circuit/

      Reply
  4. Denis says

    October 12, 2020 at 12:12 am

    hello I make the ic 7812 current booster circuit with 2 transistors to have a load of 7 amp, how I can put an automatic cut off on this circuit
    Thank you

    Reply
    • admin says

      October 13, 2020 at 6:32 pm

      what kind of auto cut off are you asking for? please explain it in detail

      Reply

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